CH_3-CH=CH_2+NOCl to P. Identify the product. | vedclass

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(A) The reaction of propene with nitrosyl chloride $(NOCl)$ is an Electrophilic Addition Reaction $(EAR)$.In $NOCl$,the bond breaks heterolytically to

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(A) The reaction of propene with nitrosyl chloride $(NOCl)$ is an Electrophilic Addition Reaction $(EAR)$.In $NOCl$,the bond breaks heterolytically to form $NO^+$ (nitrosonium ion) as the electrophile and $Cl^-$ as the nucleophile.$NO^+$ attacks the double bond of propene to form a more stable carbocation intermediate (secondary carbocation).$CH_3-CH=CH_2 + NO^+ 	o CH_3-CH^+-CH_2-NO$Then,the nucleophile $Cl^-$ attacks the carbocation to form the final product:$CH_3-CH(Cl)-CH_2-NO$Thus,the product is $1-nitro-2-chloropropane$ (or $2-chloro-1-nitropropane$ depending on nomenclature,but based on the structure,it is $CH_3-CH(Cl)-CH_2(NO)$).

$CH_3-CH=CH_2+NOCl \to P$. Identify the product.

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