Br_2 + 2X^{-} to 2Br^{-} + X_2Cl_2 + 2Y^{-} t | vedclass

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Question

(C) The reactions follow the principle that a stronger halogen (higher oxidation potential) can displace a weaker halogen (lower oxidation potential)

Vedclass · Accepted Answer

$X_2 = Cl_2$

Vedclass · Answer

(C) The reactions follow the principle that a stronger halogen (higher oxidation potential) can displace a weaker halogen (lower oxidation potential) from its halide salt.The order of oxidizing power is $F_2 > Cl_2 > Br_2 > I_2$.In the first reaction,$Br_2 + 2X^{-} 	o 2Br^{-} + X_2$,$Br_2$ can displace $I^{-}$ to form $I_2$ $(X_2 = I_2)$. It cannot displace $Cl^{-}$ because $Cl_2$ is a stronger oxidant than $Br_2$.In the second reaction,$Cl_2 + 2Y^{-} 	o 2Cl^{-} + Y_2$,$Cl_2$ can displace $Br^{-}$ $(Y_2 = Br_2)$ or $I^{-}$ $(Y_2 = I_2)$.Comparing the options:$A$: $X_2 = I_2$ is possible.$B$: $Y_2 = I_2$ is possible.$C$: $X_2 = Cl_2$ is incorrect because $Br_2$ cannot oxidize $Cl^{-}$ to $Cl_2$.$D$: $Y_2 = Br_2$ is possible.Therefore,the incorrect match is $X_2 = Cl_2$.

$Br_2 + 2X^{-} \to 2Br^{-} + X_2$
$Cl_2 + 2Y^{-} \to 2Cl^{-} + Y_2$
The incorrect match regarding the above reactions is:

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$Br_2 + 2X^{-} \to 2Br^{-} + X_2$$Cl_2 + 2Y^{-} \to 2Cl^{-} + Y_2$The incorrect match regarding the above reactions is: