$(CH_3)_2CHBr$ $\xrightarrow[(2) CuI]{(1) Li} (A)$ $\xrightarrow{(CH_3)_2CHCH_2Br} B$.
$'B'$ is

  • A
    $(CH_3)_2CHCH_2CH_3$
  • B
    $(CH_3)_2CHCH(CH_3)_2$
  • C
    $(CH_3)_2CHCH_2CH(CH_3)_2$
  • D
    $(CH_3)_2CHCH_2CH_2CH(CH_3)_2$

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