The IUPAC name of the given compound is: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority and is attached to the ring,so the pare

Vedclass · Accepted Answer

$4-$Formyl$-2-$oxocyclohexanecarboxylic acid

Vedclass · Answer

(B) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority and is attached to the ring,so the parent name is cyclohexanecarboxylic acid. $2$. Number the ring: Start numbering from the carbon attached to the $-COOH$ group as $C-1$. $3$. Assign positions to other substituents: The ketone group $(=O)$ is at position $2$ and the formyl group $(-CHO)$ is at position $4$. $4$. Combine the names: The substituents are $4-$formyl and $2-$oxo. Arranging them alphabetically,we get $4-$formyl$-2-$oxocyclohexanecarboxylic acid.

The $IUPAC$ name of the given compound is:

Similar Questions

The $IUPAC$ name of the following compound is

The name of $ClH_2C-C(Br)=C(Br)-CH_2Cl$ according to $IUPAC$ nomenclature system is:

$IUPAC$ name of $(CH_3)_2CH-CHO$ is:

The $IUPAC$ name of the given compound $CH_3-CH=CH-COOC_2H_5$ is

What is the correct $IUPAC$ name of the following structure? Explain.
$CH_3-CH_2-CH(CH_2-CH_3)-CH_2-CH_2-CH(CH_3)-CH_2-CH_3$
$(i)$ $3-$ethyl$-6-$methyloctane
$(ii)$ $3-$methyl$-6-$ethyloctane
$(iii)$ $6-$methyl$-3-$ethyloctane

Vedclass Test Series

Exam Paper Generator

Online Exam Module