The S.I. unit of the gas constant R is: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The ideal gas equation is given by $PV = nRT$.Rearranging for $R$,we get $R = \frac{PV}{nT}$.In $S.I.$ units,pressure $P$ is measured in $Pascal$

Vedclass · Accepted Answer

$8.31 \, J \, K^{-1} \, mol^{-1}$

Vedclass · Answer

(C) The ideal gas equation is given by $PV = nRT$.Rearranging for $R$,we get $R = \frac{PV}{nT}$.In $S.I.$ units,pressure $P$ is measured in $Pascal$ ($Pa$ or $N \, m^{-2}$),volume $V$ in $m^3$,and temperature $T$ in $K$.Substituting these units: $R = \frac{(N \, m^{-2}) 	imes (m^3)}{mol 	imes K} = N \, m \, K^{-1} \, mol^{-1} = J \, K^{-1} \, mol^{-1}$.The value of the universal gas constant $R$ in $S.I.$ units is $8.314 \, J \, K^{-1} \, mol^{-1}$.

The $S.I.$ unit of the gas constant $R$ is:

Similar Questions

Match the following gas laws with their respective equations.

$A$ certain sample of gas has a volume of $0.2 \ L$ at one atmosphere pressure and $273.15 \ K$. What is the volume of gas at $273.15 \ ^{\circ}C$ at the same pressure (in $L$)?

The pressure and temperature of $4 \ dm^3$ of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be ............. $dm^3$.

If $4 \ g$ of $O_2$ and $2 \ g$ of $H_2$ are filled in a $1 \ L$ bulb at $0 \ ^oC$,the total pressure of the mixture will be...... (in $atm$)

If $2 \, \text{moles}$ of an ideal gas occupy a volume of $44.8 \, L$ at a temperature of $546 \, K$,what will be the pressure in $atm$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module