KO_2 + CO_2 + H_2O xrightarrow{text{more } CO | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of potassium superoxide $(KO_2)$ with carbon dioxide $(CO_2)$ and water $(H_2O)$ proceeds as follows:$4KO_2 + 2CO_2 + 2H_2O \rightarr

Vedclass · Accepted Answer

$KHCO_3, O_2$

Vedclass · Answer

(B) The reaction of potassium superoxide $(KO_2)$ with carbon dioxide $(CO_2)$ and water $(H_2O)$ proceeds as follows:$4KO_2 + 2CO_2 + 2H_2O \rightarrow 4KHCO_3 + 3O_2$In the presence of excess $CO_2$,the primary product formed is potassium bicarbonate $(KHCO_3)$ and oxygen gas $(O_2)$ is released.Therefore,$[X] = KHCO_3$ and $[Y] = O_2$.

$KO_2 + CO_2 + H_2O \xrightarrow{\text{more } CO_2} [X] + [Y]$
Products $[X]$ and $[Y]$ are respectively

Similar Questions

What is sodium amalgam and how is it obtained?

Select the $INCORRECT$ statement regarding the solution of an alkali metal in liquid $NH_3$?

Discuss the differences in properties observed between lithium and the rest of the alkali metals.

What is released when washing soda is heated?

Which of the following metals produces hydrogen gas when heated with hot concentrated alkali?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$KO_2 + CO_2 + H_2O \xrightarrow{\text{more } CO_2} [X] + [Y]$Products $[X]$ and $[Y]$ are respectively