$PbI_4$ does not exist because

  • A
    iodine is not reactive
  • B
    $Pb(IV)$ is oxidizing and $I^-$ is a strong reducing agent
  • C
    $Pb(IV)$ is less stable than $Pb(II)$
  • D
    $Pb^{4+}$ is not easily formed

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For correct statement use $T$ and for incorrect use $F$:
$(A)$ Hydrolysis of Marshall's acid gives $H_2SO_4$ and $H_2O_2$ as final products.
$(B)$ In $SCNSiH_3$ structure,the geometry around $N$ is bent.
$(C)$ The basic unit for silicates is $SiO_4^{4-}$.
$(D)$ $NH_4Cl + NaOH \to NH_3 \uparrow$.

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Assertion $(A): [SiF_6]^{2-}$ is formed but $[SiCl_6]^{2-}$ is not.
Reason $(R):$ Electronegativity $(EN)$ of $F$ is higher than $EN$ of $Cl$.

Which element among the following has the maximum bond energy?

Bleaching powder is obtained by the action of chlorine on which of the following?

In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
$\underline{P}OCl_3 + H_2O \longrightarrow H_3PO_4 + HCl$

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