AgNO_3 xrightarrow{Delta} (W) + (X) + O_2(X) | vedclass

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(C) $1$. Thermal decomposition of $AgNO_3$: $2AgNO_3 \xrightarrow{\Delta} 2Ag + 2NO_2 + O_2$. Thus,$(W) = Ag$ and $(X) = NO_2$.$2$. Reaction of $(X)$

Vedclass · Accepted Answer

$W = Ag, X = NO_2, Y = AgNO_3, Z = Na_3[Ag(S_2O_3)_2]$

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(C) $1$. Thermal decomposition of $AgNO_3$: $2AgNO_3 \xrightarrow{\Delta} 2Ag + 2NO_2 + O_2$. Thus,$(W) = Ag$ and $(X) = NO_2$.$2$. Reaction of $(X)$ with water: $2NO_2 + H_2O \longrightarrow HNO_2 + HNO_3$. This confirms $(X) = NO_2$.$3$. Reaction of $(W)$ with $HNO_3$: $3Ag + 4HNO_3 \longrightarrow 3AgNO_3 + NO + 2H_2O$. Thus,$(Y) = AgNO_3$.$4$. Reaction of $(Y)$ with excess $Na_2S_2O_3$: $AgNO_3 + 2Na_2S_2O_3 \longrightarrow Na_3[Ag(S_2O_3)_2] + NaNO_3$. Thus,$(Z) = Na_3[Ag(S_2O_3)_2]$.

$AgNO_3 \xrightarrow{\Delta} (W) + (X) + O_2$
$(X) + H_2O \longrightarrow HNO_2 + HNO_3$
$(W) + HNO_3 \longrightarrow Y + NO + H_2O$
$(Y) + Na_2S_2O_3(\text{excess}) \longrightarrow (Z) + NaNO_3$
Identify $(W)$ to $(Z)$.

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$AgNO_3 \xrightarrow{\Delta} (W) + (X) + O_2$$(X) + H_2O \longrightarrow HNO_2 + HNO_3$$(W) + HNO_3 \longrightarrow Y + NO + H_2O$$(Y) + Na_2S_2O_3(\text{excess}) \longrightarrow (Z) + NaNO_3$Identify $(W)$ to $(Z)$.