(B) In the $N_2O_4$ dimer,the unpaired electrons on the nitrogen atoms of two $NO_2$ molecules pair up to form a weak $N-N$ bond.Due to resonance,the

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$A$ weak $N-N$ bond is formed and all four $N-O$ bonds become equal.

(B) In the $N_2O_4$ dimer,the unpaired electrons on the nitrogen atoms of two $NO_2$ molecules pair up to form a weak $N-N$ bond.Due to resonance,the electron density is delocalized,making all four $N-O$ bonds equivalent in length and strength.

Class 11 Chemistry Chemical Bonding and Molecular Structure Resonance

Easy

During the formation of the dimer $N_2O_4$ from two molecules of $NO_2$,what happens to the unpaired electron on the nitrogen atom of each $NO_2$ molecule?

A
$A$ weak $N-N$ bond is formed,two $N-O$ bonds become equal,and the other two $N-O$ bonds become unequal.
B
$A$ weak $N-N$ bond is formed and all four $N-O$ bonds become equal.
C
$A$ weak $N-N$ bond is formed and all four $N-O$ bonds become unequal.
D
$A$ strong $N-N$ bond is formed and all four $N-O$ bonds become equal.