Which of the following sequences represents the correct increasing order of bond angles in the given molecules?
- A$OF_2 < H_2O < OCl_2 < ClO_2$
- B$H_2O < OF_2 < OCl_2 < ClO_2$
- C$OCl_2 < ClO_2 < H_2O < OF_2$
- D$ClO_2 < OF_2 < OCl_2 < H_2O$
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Similar Questions
Arrange the following molecules in the correct order of their bond angles:
$S_8$ $A$ $P_4$ $B$ $S_6$ $C$ $O_3$ $D$
| $S_8$ | $A$ |
| $P_4$ | $B$ |
| $S_6$ | $C$ |
| $O_3$ | $D$ |
For $OF_2$ molecule,consider the following statements:
$A$. Number of lone pairs on oxygen is $2$.
$B$. $FOF$ bond angle is less than $104.5^{\circ}$.
$C$. Oxidation state of $O$ is $-2$.
$D$. Molecule is bent $V$-shaped.
$E$. Molecular geometry is linear.
Which of the following options is correct?
$A$. Number of lone pairs on oxygen is $2$.
$B$. $FOF$ bond angle is less than $104.5^{\circ}$.
$C$. Oxidation state of $O$ is $-2$.
$D$. Molecule is bent $V$-shaped.
$E$. Molecular geometry is linear.
Which of the following options is correct?
Which of the following is a non-linear molecule?
Easy
View SolutionThe $HNH$ angle value is higher than $HPH, HAsH$ and $HSbH$ angles. Why?
[Hint: Can be explained on the basis of $sp^{3}$ hybridisation in $NH_{3}$ and only $s-p$ bonding between hydrogen and other elements of the group].
[Hint: Can be explained on the basis of $sp^{3}$ hybridisation in $NH_{3}$ and only $s-p$ bonding between hydrogen and other elements of the group].
Medium
View SolutionThe geometry of $I_{3}^{-}$ is
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