What is the correct order of decreasing oxida | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the oxidation state of iodine $(I)$ in each compound:$1$. In $HIO_4$: Let the oxidation state of $I$ be $x$. $1 + x + 4(-2) = 0 \impl

Vedclass · Accepted Answer

$HIO_4, ICl_5, I_2, HI$

Vedclass · Answer

(B) To determine the oxidation state of iodine $(I)$ in each compound:$1$. In $HIO_4$: Let the oxidation state of $I$ be $x$. $1 + x + 4(-2) = 0 \implies x = +7$.$2$. In $ICl_5$: Let the oxidation state of $I$ be $x$. $x + 5(-1) = 0 \implies x = +5$.$3$. In $I_2$: The oxidation state of iodine in its elemental form is $0$.$4$. In $HI$: Let the oxidation state of $I$ be $x$. $1 + x = 0 \implies x = -1$.Thus,the decreasing order of oxidation states is $+7 (HIO_4) > +5 (ICl_5) > 0 (I_2) > -1 (HI)$.

What is the correct order of decreasing oxidation state of iodine in the following compounds?

Similar Questions

The oxidation number of fluorine in $F_2O$ is

What are the oxidation states of $P$ in $H_4P_2O_5$,$H_4P_2O_6$,and $H_4P_2O_7$ respectively?

What is the oxidation state of phosphorus in the phosphate ion $(PO_4^{3-})$?

An acidic solution of sodium thiosulfate is unstable because in thiosulfate,the two sulfur atoms have different oxidation states of:

In which of the following compounds does nitrogen exhibit the highest oxidation state?

Vedclass Test Series

Exam Paper Generator

Online Exam Module