What is the type of hybridization of the cent | vedclass

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(B) The hybridization of the central atom is calculated using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence electro

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$sp^3d, sp^3d, sp^3d^2$

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(B) The hybridization of the central atom is calculated using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $I_3^-$: $H = \frac{1}{2}(7 + 2 + 1) = 5$,which corresponds to $sp^3d$ hybridization.For $ICl_2^-$: $H = \frac{1}{2}(7 + 2 + 1) = 5$,which corresponds to $sp^3d$ hybridization.For $ICl_4^-$: $H = \frac{1}{2}(7 + 4 + 1) = 6$,which corresponds to $sp^3d^2$ hybridization.Thus,the correct sequence is $sp^3d, sp^3d, sp^3d^2$.

What is the type of hybridization of the central atom in $I_3^-$,$ICl_2^-$,and $ICl_4^-$ respectively?

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