What is the hybridization state of the chlori | vedclass

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(C) The hybridization of the central atom is calculated using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence electro

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$sp^3$ in all species

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(C) The hybridization of the central atom is calculated using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $ClO_4^-$: $H = \frac{1}{2}(7 + 0 - 0 + 1) = 4$ ($sp^3$ hybridization).For $ClO_3^-$: $H = \frac{1}{2}(7 + 0 - 0 + 1) = 4$ ($sp^3$ hybridization).For $ClO_2^-$: $H = \frac{1}{2}(7 + 0 - 0 + 1) = 4$ ($sp^3$ hybridization).Thus,the chlorine atom in all these ions is $sp^3$ hybridized.

What is the hybridization state of the chlorine atom in $ClO_4^-$,$ClO_3^-$,and $ClO_2^-$ ions,respectively?

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