What is the hybridization and structure of Xe | vedclass

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Question

(C) In $XeF_4$,the central atom $Xe$ has $8$ valence electrons.It forms $4$ bonds with $F$ atoms and has $2$ lone pairs.Total electron pairs = $4 	ex

Vedclass · Accepted Answer

$sp^3d^2$,Square planar

Vedclass · Answer

(C) In $XeF_4$,the central atom $Xe$ has $8$ valence electrons.It forms $4$ bonds with $F$ atoms and has $2$ lone pairs.Total electron pairs = $4 	ext{ (bond pairs)} + 2 	ext{ (lone pairs)} = 6$.Therefore,the hybridization is $sp^3d^2$.According to $VSEPR$ theory,with $4$ bond pairs and $2$ lone pairs,the geometry is octahedral,but the shape is square planar.

List-$I$	List-$II$
$(a)$ $SF_6$	$(i)$ $sp^3d^2$
$(b)$ $PCl_5$	(ii) $sp^3d$
$(c)$ $XeF_4$	(iii) $sp^3d^3$
$(d)$ $IF_7$	(iv) $sp^3d^2$

What is the hybridization and structure of $XeF_4$?

Similar Questions

Match the following:
List-$I$ List-$II$
$(a)$ $SF_6$ $(i)$ $sp^3d^2$
$(b)$ $PCl_5$ (ii) $sp^3d$
$(c)$ $XeF_4$ (iii) $sp^3d^3$
$(d)$ $IF_7$ (iv) $sp^3d^2$

The correct answer is:

Why does boron trifluoride behave as a Lewis acid?

The percentage of $p$-character in the orbitals forming $P-P$ bonds in $P_4$ is

Which of the following processes involves a change in bond angle along with a change in hybridization?

What is the shape of the molecule $CH_2 = CH - CH = CH_2$?

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