Identify the product A in the following react | vedclass

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(A) The reaction of $Methylenecyclohexane$ with $Br_2$ in the presence of $H_2O$ is a halohydrin formation reaction.$1$. The double bond attacks the $

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$1-$(bromomethyl)cyclohexan$-1-$ol

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(A) The reaction of $Methylenecyclohexane$ with $Br_2$ in the presence of $H_2O$ is a halohydrin formation reaction.$1$. The double bond attacks the $Br_2$ molecule to form a cyclic bromonium ion intermediate.$2$. Water $(H_2O)$,acting as a nucleophile,attacks the more substituted carbon of the bromonium ion because it can better stabilize the partial positive charge in the transition state.$3$. This leads to the formation of $1-(bromomethyl)cyclohexan-1-ol$ as the major product.The reaction is:$C_6H_{10}=CH_2 + Br_2 + H_2O \rightarrow C_6H_{10}(OH)(CH_2Br) + HBr$

Identify the product $A$ in the following reaction:
$Methylenecyclohexane \xrightarrow{Br_2 / H_2O} A$

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Identify the product $A$ in the following reaction:$Methylenecyclohexane \xrightarrow{Br_2 / H_2O} A$