3.2 moles of hydrogen iodide were heated in a | vedclass

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(A) The degree of dissociation $(\alpha)$ is given as $22 \%$,which is $0.22$.The initial number of moles of $HI$ is $3.2$.The number of moles of $HI$

Vedclass · Accepted Answer

$2.496$

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(A) The degree of dissociation $(\alpha)$ is given as $22 \%$,which is $0.22$.The initial number of moles of $HI$ is $3.2$.The number of moles of $HI$ dissociated at equilibrium is calculated as: $	ext{Moles dissociated} = 	ext{Initial moles} 	imes \alpha = 3.2 	imes 0.22 = 0.704$.The number of moles of $HI$ remaining at equilibrium is: $	ext{Moles at equilibrium} = 	ext{Initial moles} - 	ext{Moles dissociated} = 3.2 - 0.704 = 2.496$.

$3.2$ moles of hydrogen iodide were heated in a sealed bulb at $444 \, ^oC$ until the equilibrium state was reached. Its degree of dissociation at this temperature was found to be $22 \%$. The number of moles of hydrogen iodide present at equilibrium are:

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