Ph^{-}MgBr + CH_3-CH(OH)-CH_3 to A. What is t | vedclass

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(A) Grignard reagents $(R^{-}MgX)$ are strong bases. They react with compounds containing active hydrogen (like alcohols,water,or acids) to undergo an

Vedclass · Accepted Answer

Benzene

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(A) Grignard reagents $(R^{-}MgX)$ are strong bases. They react with compounds containing active hydrogen (like alcohols,water,or acids) to undergo an acid-base reaction,producing a hydrocarbon.In this reaction,the phenyl group $(Ph^{-})$ from the Grignard reagent abstracts the acidic proton from the hydroxyl group of isopropanol to form benzene.$Ph^{-}MgBr + CH_3-CH(OH)-CH_3 	o C_6H_6 + (CH_3)_2CH-OMgBr$.Therefore,product $A$ is Benzene.

$Ph^{-}MgBr + CH_3-CH(OH)-CH_3 \to A$. What is the product $A$?

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