$NH_3$ can not be obtained by

  • A
    heating of $NH_4NO_3$
  • B
    heating of $NH_4Cl$
  • C
    heating of $(NH_4)_2CO_3$
  • D
    None

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$A$. Reducing nature increases from $NH_3$ to $BiH_3$
$B$. Tendency to donate lone pair of electrons decreases from $NH_3$ to $BiH_3$
$C$. The stability of hydrides decreases from $NH_3$ to $BiH_3$
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The number of pentagons in $C_{60}$ and trigons (triangles) in white phosphorus,respectively,are

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