Br_2 + NaOH xrightarrow{R.T.} Y + ZIf Y gives | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of bromine with cold dilute sodium hydroxide is: $Br_2 + 2NaOH \longrightarrow NaBr + NaBrO + H_2O$.Here,$Y$ is $NaBr$ and $Z$ is $Na

Vedclass · Accepted Answer

$Al^{3+}(aq.)$

Vedclass · Answer

(C) The reaction of bromine with cold dilute sodium hydroxide is: $Br_2 + 2NaOH \longrightarrow NaBr + NaBrO + H_2O$.Here,$Y$ is $NaBr$ and $Z$ is $NaBrO$.$NaBr$ gives a yellow precipitate of $AgBr$ with $AgNO_3$.$NaBrO$ (sodium hypobromite) acts as an oxidizing agent.It can oxidize $Cr^{3+}$ to $Cr^{6+}$,$Fe^{2+}$ to $Fe^{3+}$,and $Sn^{2+}$ to $Sn^{4+}$.However,$Al^{3+}$ is already in its highest stable oxidation state $(+3)$,so it cannot be further oxidized by $NaBrO$.

$Br_2 + NaOH \xrightarrow{R.T.} Y + Z$
If $Y$ gives a precipitate with $AgNO_3$,then $Z$ does not undergo a reaction with:

Similar Questions

Conc. $H_2SO_4$ cannot be used to prepare $HBr$ from $NaBr$ because it :

Bromine is commercially prepared from sea water by displacement reaction:
$Cl_2 + 2Br^{-} (aq.) \to 2Cl^{-}(aq.) + Br_2$
$Br_2$ gas thus formed is dissolved into a solution of $Na_2CO_3$ and then pure $Br_2$ is obtained by treatment of the solution with:

Marine plants are an important source of ........ .

Which one will liberate $Br_2$ from $KBr$?

Which of the following can not undergo hydrolysis?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Br_2 + NaOH \xrightarrow{R.T.} Y + Z$If $Y$ gives a precipitate with $AgNO_3$,then $Z$ does not undergo a reaction with: