(C) Using the ideal gas equation: $PV = nRT$Given: $P = 10 \ atm$,$V = 0.082 \ L$,$T = 400 \ K$,$R = 0.082 \ L \ atm \ K^{-1} \ mol^{-1}$$n = \frac{PV

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) Using the ideal gas equation: $PV = nRT$Given: $P = 10 \ atm$,$V = 0.082 \ L$,$T = 400 \ K$,$R = 0.082 \ L \ atm \ K^{-1} \ mol^{-1}$$n = \frac{PV}{RT} = \frac{10 \times 0.082}{0.082 \times 400} = \frac{10}{400} = 0.025 \ mol$Number of molecules = $n \times N_A = 0.025 \times 6.022 \times 10^{23} \approx 1.5 \times 10^{22}$ molecules.

Class 11 Chemistry States of Matter Ideal gas equation and Related gas laws

Medium

What is the number of molecules in $0.082 \ L$ of an ideal gas kept at a temperature of $400 \ K$ and a pressure of $10 \ atm$?

A
$1.5 \times 10^{23}$
B
$3 \times 10^{23}$
C
$1.5 \times 10^{22}$
D
$2.5 \times 10^{21}$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

States of Matter

Subtopic

Ideal gas equation and Related gas laws

Derive the relation between density $(d)$ and molar mass $(M)$ for an ideal gas.

Medium

View Solution

At $NTP$,$10 \ g$ of a gas occupies $5 \ L$ of volume. At what temperature will the volume become double for the same mass of gas at the same pressure?

Easy

View Solution

$300 \ mL$ of a gas at $27 \ ^\circ C$ is cooled to $-3 \ ^\circ C$ at constant pressure. The final volume is ................ $mL$.

Medium

View Solution

For an ideal gas,the $V$ vs $T$ plot at constant pressures $P_1$ and $P_2$ is shown in the figure. Which of the following is correct?

Easy

View Solution

Explain the law relating pressure and temperature.

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

What is the number of molecules in $0.082 \ L$ of an ideal gas kept at a temperature of $400 \ K$ and a pressure of $10 \ atm$?

Similar Questions

Derive the relation between density $(d)$ and molar mass $(M)$ for an ideal gas.

At $NTP$,$10 \ g$ of a gas occupies $5 \ L$ of volume. At what temperature will the volume become double for the same mass of gas at the same pressure?

$300 \ mL$ of a gas at $27 \ ^\circ C$ is cooled to $-3 \ ^\circ C$ at constant pressure. The final volume is ................ $mL$.

For an ideal gas,the $V$ vs $T$ plot at constant pressures $P_1$ and $P_2$ is shown in the figure. Which of the following is correct?

Explain the law relating pressure and temperature.

Vedclass Test Series

Exam Paper Generator

Online Exam Module