The mass of 500 , cm^3 of a gas at STP is 0.5 | vedclass

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Question

(C) At $STP$,the volume of $1 \, mole$ of any gas is $22.4 \, L$ or $22400 \, cm^3$. Given: Volume $V = 500 \, cm^3$,Mass $m = 0.581 \, g$. Density $\

Vedclass · Accepted Answer

$C_2H_2$

Vedclass · Answer

(C) At $STP$,the volume of $1 \, mole$ of any gas is $22.4 \, L$ or $22400 \, cm^3$. Given: Volume $V = 500 \, cm^3$,Mass $m = 0.581 \, g$. Density $ho = \frac{m}{V} = \frac{0.581 \, g}{500 \, cm^3} = 0.001162 \, g/cm^3$. Molar mass $M = ho 	imes 22400 \, cm^3/mol$. $M = 0.001162 	imes 22400 \approx 26.03 \, g/mol$. The molar mass of $C_2H_2$ is $(2 	imes 12) + (2 	imes 1) = 26 \, g/mol$. Therefore,the gas is $C_2H_2$.

The mass of $500 \, cm^3$ of a gas at $STP$ is $0.581 \, g$. If the gas is a hydrocarbon,what is the gas?

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