A 50 , L container holds 0.5 , mol of O_2 gas | vedclass

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(C) The root mean square $(rms)$ speed of gas molecules is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$.Here,$R$ is the universal gas consta

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(C) The root mean square $(rms)$ speed of gas molecules is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$.Here,$R$ is the universal gas constant,$T$ is the absolute temperature in Kelvin,and $M$ is the molar mass of the gas.The $rms$ speed depends only on the temperature $(T)$ and the molar mass $(M)$ of the gas.Since the temperature remains constant $(27 \, ^oC)$ and the molar mass of $O_2$ is constant,the $rms$ speed will remain unchanged regardless of the number of molecules removed.

$A$ $50 \, L$ container holds $0.5 \, mol$ of $O_2$ gas at $27 \, ^oC$ and $2 \, atm$ pressure. If half of the $O_2$ molecules are removed from the container,what happens to the $rms$ speed of the $O_2$ molecules?

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