The kinetic energy of an electron in the grou | vedclass

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(B) According to Bohr's model,the kinetic energy $(KE)$ of an electron in a hydrogen-like species is given by the formula: $KE = \frac{1}{2} \frac{kZe

Vedclass · Accepted Answer

$e^2 / 2\pi\varepsilon_0 r$

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(B) According to Bohr's model,the kinetic energy $(KE)$ of an electron in a hydrogen-like species is given by the formula: $KE = \frac{1}{2} \frac{kZe^2}{r}$.Substituting the Coulomb constant $k = \frac{1}{4\pi\varepsilon_0}$ and the atomic number $Z = 4$ for $Be^{3+}$:$KE = \frac{1}{2} 	imes \frac{1}{4\pi\varepsilon_0} 	imes \frac{4e^2}{r}$.Simplifying the expression:$KE = \frac{4e^2}{8\pi\varepsilon_0 r} = \frac{e^2}{2\pi\varepsilon_0 r}$.

The kinetic energy of an electron in the ground state of a $Be^{3+}$ ion is given by:

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