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(C) Given: Mass $(m)$ = $200 \ g = 0.2 \ kg$. Velocity $(v)$ = $5 \ m/hr = 5 / 3600 \ m/s = 1.389 	imes 10^{-3} \ m/s$. Planck's constant $(h)$ = $6.

Vedclass · Accepted Answer

$2.37 	imes 10^{-30} \ m$

Vedclass · Answer

(C) Given: Mass $(m)$ = $200 \ g = 0.2 \ kg$. Velocity $(v)$ = $5 \ m/hr = 5 / 3600 \ m/s = 1.389 	imes 10^{-3} \ m/s$. Planck's constant $(h)$ = $6.626 	imes 10^{-34} \ J \cdot s$. According to de Broglie's equation: $\lambda = h / (mv)$. $\lambda = (6.626 	imes 10^{-34}) / (0.2 	imes 1.389 	imes 10^{-3})$. $\lambda = (6.626 	imes 10^{-34}) / (2.778 	imes 10^{-4})$. $\lambda \approx 2.385 	imes 10^{-30} \ m$. Comparing with the given options,the closest value is $2.37 	imes 10^{-30} \ m$.

If the velocity of a golf ball with a mass of $200 \ g$ is $5 \ m/hr$,then the wavelength associated with it will be .........

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