(C) For a given shell with principal quantum number $n$,the total number of orbitals is $n^2$.Each orbital can hold a maximum of $2$ electrons,one wit

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(C) For a given shell with principal quantum number $n$,the total number of orbitals is $n^2$.Each orbital can hold a maximum of $2$ electrons,one with spin $+1/2$ and one with spin $-1/2$.Therefore,the number of electrons with the same spin (e.g.,only $+1/2$ or only $-1/2$) in a shell is equal to the total number of orbitals,which is $n^2$.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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What is the maximum number of electrons with the same spin that can be accommodated in a shell with principal quantum number $n$?

A
$2n^2$
B
$2n$
C
$n^2$
D
$n^2/2$

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Class 11 Questions

Class 11

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Chapter

Structure of Atom

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Quantum number, Electronic configuration and Shape of orbitals

Which of the following orbitals will have $2$ nodal planes and $4$ total nodes?

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The electronic configuration of cobalt ($Co$,atomic number $27$) is:

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In the case of a hydrogen atom,which of the following transitions does not involve the absorption or emission of energy?

Medium

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When the principal quantum number is $n = 3$,the possible values of the azimuthal quantum number $(l)$ are:

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For a given azimuthal quantum number $(l)$,the total number of magnetic quantum numbers $(m)$ is given by:

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What is the maximum number of electrons with the same spin that can be accommodated in a shell with principal quantum number $n$?

Similar Questions

Which of the following orbitals will have $2$ nodal planes and $4$ total nodes?

The electronic configuration of cobalt ($Co$,atomic number $27$) is:

In the case of a hydrogen atom,which of the following transitions does not involve the absorption or emission of energy?

When the principal quantum number is $n = 3$,the possible values of the azimuthal quantum number $(l)$ are:

For a given azimuthal quantum number $(l)$,the total number of magnetic quantum numbers $(m)$ is given by:

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