If the quantum number values for the valence | vedclass

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(D) The given quantum numbers $n = 4, l = 0, m = 0$ correspond to the $4s$ orbital. This indicates that the valence electron is in the $4s$ subshell.

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$19$ or $20$

Vedclass · Answer

(D) The given quantum numbers $n = 4, l = 0, m = 0$ correspond to the $4s$ orbital. This indicates that the valence electron is in the $4s$ subshell. The electronic configuration of the atom must end in $4s^1$ or $4s^2$. If the configuration ends in $4s^1$,the element is Potassium $(K)$,which has an atomic number of $19$. If the configuration ends in $4s^2$,the element is Calcium $(Ca)$,which has an atomic number of $20$. Therefore,the atomic number can be $19$ or $20$.

List-$I$ (Element)	List-$II$ (Electronic Configuration)
$A. N$	$I. [Ar] 3d^{10} 4s^2 4p^5$
$B. S$	$II. [Ne] 3s^2 3p^4$
$C. Br$	$III. [He] 2s^2 2p^3$
$D. Kr$	$IV. [Ar] 3d^{10} 4s^2 4p^6$

If the quantum number values for the valence shell electron of an atom are $n = 4, l = 0, m = 0$,then the atomic number of the element could be .........

Similar Questions

For principal quantum number $n = 4$,the total number of orbitals having $l = 3$ is:

In which of the following cases are both the Pauli exclusion principle and Hund's rule violated?

Identify the pair of orbitals having similar $(n + l)$ values from the following.

Match List-$I$ with List-$II$.

List-$I$ (Element) List-$II$ (Electronic Configuration)

$A. N$ $I. [Ar] 3d^{10} 4s^2 4p^5$

$B. S$ $II. [Ne] 3s^2 3p^4$

$C. Br$ $III. [He] 2s^2 2p^3$

$D. Kr$ $IV. [Ar] 3d^{10} 4s^2 4p^6$

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What is the number of unpaired electrons in a ferrous ion $(Fe^{2+})$?

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