The number of oxygen atoms in a solution prep | vedclass

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(C) Molar mass of sucrose $(C_{12}H_{22}O_{11})$ = $342 \ g/mol$. Moles of sucrose = $\frac{34.2 \ g}{342 \ g/mol} = 0.1 \ mol$. Oxygen atoms from suc

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$3.67 	imes 10^{24}$

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(C) Molar mass of sucrose $(C_{12}H_{22}O_{11})$ = $342 \ g/mol$. Moles of sucrose = $\frac{34.2 \ g}{342 \ g/mol} = 0.1 \ mol$. Oxygen atoms from sucrose = $0.1 \ mol 	imes 11 = 1.1 \ mol$. Molar mass of water $(H_2O)$ = $18 \ g/mol$. Moles of water = $\frac{90 \ g}{18 \ g/mol} = 5 \ mol$. Oxygen atoms from water = $5 \ mol 	imes 1 = 5 \ mol$. Total moles of oxygen atoms = $1.1 + 5 = 6.1 \ mol$. Number of oxygen atoms = $6.1 	imes 6.022 	imes 10^{23} \approx 3.67 	imes 10^{24}$.

The number of oxygen atoms in a solution prepared by dissolving $34.2 \ g$ of sucrose in $90 \ g$ of water is:

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