The atomic weights of two elements A and B ar | vedclass

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(C) Number of moles of $A = \frac{x}{40}$.Since $x \ g$ of $A$ contains $y$ atoms,the number of atoms is given by $n 	imes N_A$,where $n$ is the numb

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$y$

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(C) Number of moles of $A = \frac{x}{40}$.Since $x \ g$ of $A$ contains $y$ atoms,the number of atoms is given by $n 	imes N_A$,where $n$ is the number of moles.Number of moles of $B = \frac{2x}{80} = \frac{x}{40}$.Since the number of moles of $A$ and $B$ are equal,the number of atoms in $2x \ g$ of $B$ will also be equal to the number of atoms in $x \ g$ of $A$.Therefore,the number of atoms in $B = y$.

The atomic weights of two elements $A$ and $B$ are $40$ and $80$ respectively. If $x \ g$ of $A$ contains $y$ atoms,how many atoms are present in $2x \ g$ of $B$?

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