x_1 , g of a compound combines with O_2 to gi | vedclass

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(B) The reaction is: $	ext{Compound} + O_2 ightarrow 	ext{Oxide of the compound}$.The mass of $O_2$ that combines with the compound is $(x_2 - x_1

Vedclass · Accepted Answer

$8x_1 / (x_2 - x_1)$

Vedclass · Answer

(B) The reaction is: $	ext{Compound} + O_2 ightarrow 	ext{Oxide of the compound}$.The mass of $O_2$ that combines with the compound is $(x_2 - x_1) \, g$.By definition,the equivalent mass of a substance is the mass that combines with $8 \, g$ of oxygen.Since $(x_2 - x_1) \, g$ of $O_2$ combines with $x_1 \, g$ of the compound,Therefore,$8 \, g$ of $O_2$ will combine with: $\frac{x_1 	imes 8}{x_2 - x_1} \, g$ of the compound.Thus,the equivalent mass of the compound is $\frac{8x_1}{x_2 - x_1}$.

Column $-I$	Column $-II$
$(i)$ Barium sulphate	$(a)$ $1877 \ g/mol$
$(ii)$ Magnesium pyrophosphate	$(b)$ $235 \ g/mol$
$(iii)$ Ammonium phosphomolybdate	$(c)$ $188 \ g/mol$
$(iv)$ Silver chloride	$(d)$ $222 \ g/mol$
$(v)$ Silver bromide	$(e)$ $143.5 \ g/mol$
$(vi)$ Silver iodide	$(f)$ $233 \ g/mol$

$x_1 \, g$ of a compound combines with $O_2$ to give $x_2 \, g$ of oxide. The equivalent mass of the compound is .........

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