(C) The formula for vapor density relative to a gas is given by: $\text{Vapor Density} = \frac{M_{\text{substance}}}{M_{\text{reference gas}}}$Given t

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(C) The formula for vapor density relative to a gas is given by: $\text{Vapor Density} = \frac{M_{\text{substance}}}{M_{\text{reference gas}}}$Given that the reference gas is $CH_4$,its molecular mass $M_{CH_4} = 12 + (4 \times 1) = 16 \, g/mol$.Given vapor density $= 4$.Substituting the values: $4 = \frac{M_{\text{substance}}}{16}$.Therefore,$M_{\text{substance}} = 4 \times 16 = 64 \, g/mol$.

Class 11 Chemistry 6-1.Equilibrium (Chemical Equilibrium)Degree of dissociation and Vapour density

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If the vapor density of a volatile substance relative to $CH_4$ is $4$,then find the molecular mass of that substance.

A
$8$
B
$32$
C
$64$
D
$128$

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6-1.Equilibrium (Chemical Equilibrium)

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Degree of dissociation and Vapour density

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If the vapor density of a volatile substance relative to $CH_4$ is $4$,then find the molecular mass of that substance.

Similar Questions

If the density of a gas at $STP$ is $0.178 \, g/L$,find its vapor density.

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