The mole fraction of water in an 18 % , w/w a | vedclass

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(D) The concentration of $C_6H_{12}O_6$ is $18 \% \, w/w$. In $100 \, g$ of solution,the mass of $C_6H_{12}O_6$ is $18 \, g$. Moles of $C_6H_{12}O_6 =

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$0.979$

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(D) The concentration of $C_6H_{12}O_6$ is $18 \% \, w/w$. In $100 \, g$ of solution,the mass of $C_6H_{12}O_6$ is $18 \, g$. Moles of $C_6H_{12}O_6 = \frac{18}{180} = 0.1 \, mol$. Mass of $H_2O = 100 - 18 = 82 \, g$. Moles of $H_2O = \frac{82}{18} \approx 4.556 \, mol$. Mole fraction of $H_2O (X_{H_2O}) = \frac{n_{H_2O}}{n_{H_2O} + n_{C_6H_{12}O_6}} = \frac{4.556}{4.556 + 0.1} = \frac{4.556}{4.656} \approx 0.9785 \approx 0.979$.

The mole fraction of water in an $18 \% \, w/w$ aqueous solution of $C_6H_{12}O_6$ is .......

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