The radii and charges of six ions are given b | vedclass

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(D) The lattice energy $(U)$ of an ionic crystal is directly proportional to the product of the charges $(q_1, q_2)$ and inversely proportional to the

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$MZ > JX > LY$

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(D) The lattice energy $(U)$ of an ionic crystal is directly proportional to the product of the charges $(q_1, q_2)$ and inversely proportional to the sum of the ionic radii $(r_+ + r_-)$.$U \propto \frac{|q_1 	imes q_2|}{r_+ + r_-}$For $JX$: $q_1=1, q_2=1, r_+ + r_- = 0.14 + 0.14 = 0.28 \ nm$. So,$U \propto \frac{1}{0.28} \approx 3.57$.For $LY$: $q_1=1, q_2=1, r_+ + r_- = 0.18 + 0.18 = 0.36 \ nm$. So,$U \propto \frac{1}{0.36} \approx 2.78$.For $MZ$: $q_1=2, q_2=2, r_+ + r_- = 0.15 + 0.15 = 0.30 \ nm$. So,$U \propto \frac{4}{0.30} \approx 13.33$.Comparing the values: $13.33 > 3.57 > 2.78$,which corresponds to $MZ > JX > LY$.

Ion	$J^{+}$	$L^{+}$	$M^{2+}$	$X^{-}$	$Y^{-}$	$Z^{2-}$
Radius $(nm)$	$0.14$	$0.18$	$0.15$	$0.14$	$0.18$	$0.15$

The radii and charges of six ions are given below:

Ion $J^{+}$ $L^{+}$ $M^{2+}$ $X^{-}$ $Y^{-}$ $Z^{2-}$

Radius $(nm)$ $0.14$ $0.18$ $0.15$ $0.14$ $0.18$ $0.15$

If the ionic compounds $JX$,$LY$,and $MZ$ have the same crystal structure,then the correct order of their lattice energy is:

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The radii and charges of six ions are given below: Ion $J^{+}$ $L^{+}$ $M^{2+}$ $X^{-}$ $Y^{-}$ $Z^{2-}$ Radius $(nm)$ $0.14$ $0.18$ $0.15$ $0.14$ $0.18$ $0.15$ If the ionic compounds $JX$,$LY$,and $MZ$ have the same crystal structure,then the correct order of their lattice energy is: