Which of the following is the correct decreas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the bond angle,we look at the hybridization and the number of lone pairs on the central nitrogen atom:$1$. $NO^{+}_2$: The nitrogen a

Vedclass · Accepted Answer

$NO^{+}_2 > NO_2 > NO^{-}_2$

Vedclass · Answer

(C) To determine the bond angle,we look at the hybridization and the number of lone pairs on the central nitrogen atom:$1$. $NO^{+}_2$: The nitrogen atom is $sp$ hybridized with $0$ lone pairs. The geometry is linear,so the bond angle is $180^{\circ}$.$2$. $NO_2$: The nitrogen atom is $sp^2$ hybridized with $1$ unpaired electron. The geometry is bent,and the bond angle is approximately $134^{\circ}$.$3$. $NO^{-}_2$: The nitrogen atom is $sp^2$ hybridized with $1$ lone pair. The geometry is bent,and the bond angle is approximately $115^{\circ}$.Therefore,the correct decreasing order of bond angles is $NO^{+}_2 > NO_2 > NO^{-}_2$.

Which of the following is the correct decreasing order of bond angles?

Similar Questions

In which of the following molecules are all the bonds not equal?

Which one has a pyramidal structure?

The number of bonding and non-bonding electron pairs on the $N$ atom in $NO_3^-$ are respectively ..........

The shape of $XeF^{+}_3$ is

In which of the following species is the central atom not surrounded by exactly $8$ valence electrons?

Vedclass Test Series

Exam Paper Generator

Online Exam Module