Which of the following ions is not tetrahedra | vedclass

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(C) $1$. $BF_4^-$: Boron is $sp^3$ hybridized,resulting in a tetrahedral geometry.$2$. $NH_4^+$: Nitrogen is $sp^3$ hybridized with no lone pairs,resu

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$[Cu(NH_3)_4]^{2+}$

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(C) $1$. $BF_4^-$: Boron is $sp^3$ hybridized,resulting in a tetrahedral geometry.$2$. $NH_4^+$: Nitrogen is $sp^3$ hybridized with no lone pairs,resulting in a tetrahedral geometry.$3$. $[Cu(NH_3)_4]^{2+}$: Copper $(Cu^{2+})$ in this complex undergoes $dsp^2$ hybridization,which results in a square planar geometry.$4$. $NiCl_4^{2-}$: Nickel $(Ni^{2+})$ in this complex undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.Therefore,$[Cu(NH_3)_4]^{2+}$ is not tetrahedral.

Which of the following ions is not tetrahedral?

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