How is the F_2 molecule formed? | vedclass

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(A) The atomic number of fluorine $(F)$ is $9$. Its electronic configuration is $1s^2 2s^2 2p_x^2 2p_y^2 2p_z^1$. In the formation of the $F_2$ molecu

Vedclass · Accepted Answer

By axial overlap of $p-p$ orbitals

Vedclass · Answer

(A) The atomic number of fluorine $(F)$ is $9$. Its electronic configuration is $1s^2 2s^2 2p_x^2 2p_y^2 2p_z^1$. In the formation of the $F_2$ molecule,the half-filled $2p_z$ orbital of one fluorine atom overlaps axially with the half-filled $2p_z$ orbital of another fluorine atom. This axial overlap results in the formation of a sigma $(\sigma)$ bond. Therefore,the $F_2$ molecule is formed by the axial overlap of $p-p$ orbitals.

How is the $F_2$ molecule formed?

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