If the atomic number of an element is 37,then | vedclass

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(A) The atomic number of the element is $Z = 37$. The electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1$. Since the last el

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$s$ and $1$

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(A) The atomic number of the element is $Z = 37$. The electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1$. Since the last electron enters the $5s$ orbital,the element belongs to the $s$-block. The valence shell configuration is $5s^1$,which indicates it belongs to group $1$ (alkali metals). Therefore,the block is $s$ and the group is $1$.

Elements	Ore
$1$. Lithium	$a$. Beryl
$2$. Sodium	$b$. Spodumene
$3$. Beryllium	$c$. Gypsum
$4$. Calcium	$d$. Carnallite

If the atomic number of an element is $37$,then the block and group of that element will be respectively ...

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Carnallite in water dissociates to give $.....$ ions.

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Elements Ore

$1$. Lithium $a$. Beryl

$2$. Sodium $b$. Spodumene

$3$. Beryllium $c$. Gypsum

$4$. Calcium $d$. Carnallite

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