CH_3-CH(CH_3)-CH=CH_2 xrightarrow{DBr} text{P | vedclass

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(C) The reaction follows an electrophilic addition mechanism involving a carbocation intermediate.First,the electrophile $D^+$ adds to the terminal ca

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$CH_3-C(Br)(CH_3)-CH_2-CH_2D$

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(C) The reaction follows an electrophilic addition mechanism involving a carbocation intermediate.First,the electrophile $D^+$ adds to the terminal carbon of the double bond in $CH_3-CH(CH_3)-CH=CH_2$ to form a secondary carbocation: $CH_3-CH(CH_3)-C^+H-CH_2D$.Next,a $1,2$-hydride shift occurs to convert the secondary carbocation into a more stable tertiary carbocation: $CH_3-C^+(CH_3)-CH_2-CH_2D$.Finally,the nucleophile $Br^-$ attacks the tertiary carbocation to form the major product: $CH_3-C(Br)(CH_3)-CH_2-CH_2D$.

$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{DBr} \text{Product (Major)}$. The product will be:

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