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(C) The reaction of an alkene with $HBr$ in the presence of a peroxide $(R_2O_2)$ follows the anti-Markovnikov addition rule.In this reaction,the elec

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$C_6H_5-CH_2-CH_2-CH_2Br$

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(C) The reaction of an alkene with $HBr$ in the presence of a peroxide $(R_2O_2)$ follows the anti-Markovnikov addition rule.In this reaction,the electrophile $H^+$ adds to the carbon atom of the double bond that has more hydrogen atoms,and the nucleophile $Br^-$ adds to the other carbon atom.For the reactant $C_6H_5-CH_2-CH=CH_2$,the double bond is between $C_2$ and $C_3$ of the allyl chain.The $CH_2$ group has two hydrogen atoms,while the $CH$ group has one.According to the anti-Markovnikov rule,the $Br$ atom will attach to the terminal $CH_2$ carbon,and the $H$ atom will attach to the $CH$ carbon.Thus,the major product is $C_6H_5-CH_2-CH_2-CH_2Br$.

Identify the major product $X$ in the following reaction:
$C_6H_5-CH_2-CH=CH_2 \xrightarrow{HBr, R_2O_2} X$

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Identify the major product $X$ in the following reaction:$C_6H_5-CH_2-CH=CH_2 \xrightarrow{HBr, R_2O_2} X$