$(i) \, Al \, \xrightarrow{N_2} \, A$
$(ii) \, Al \, \xrightarrow{C} \, B$
Here $A$ and $B$ on hydrolysis respectively give:

  • A
    $NH_3, \, C_2H_2$
  • B
    $NO, \, CH_4$
  • C
    $NH_3, \, CH_4$
  • D
    $NO, \, C_2H_2$

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