CH equiv CH + CO + H_2O xrightarrow{Ni(CO)_4} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given reaction is the Reppe carbonylation of acetylene: $CH \equiv CH + CO + H_2O \xrightarrow{Ni(CO)_4} CH_2 = CH - COOH$. The product formed

Vedclass · Accepted Answer

The product reacts with ethyl alcohol to give ethyl butanoate.

Vedclass · Answer

(D) The given reaction is the Reppe carbonylation of acetylene: $CH \equiv CH + CO + H_2O \xrightarrow{Ni(CO)_4} CH_2 = CH - COOH$. The product formed is acrylic acid $(CH_2 = CH - COOH)$. Statement $A$ is true: Acrylic acid is an $\alpha, \beta$-unsaturated acid. Statement $B$ is true: The reaction involves the addition of $H$ and $COOH$ across the triple bond. Statement $C$ is true: The product is indeed acrylic acid. Statement $D$ is false: Acrylic acid $(CH_2 = CH - COOH)$ reacts with ethyl alcohol $(C_2H_5OH)$ to form ethyl acrylate $(CH_2 = CH - COOC_2H_5)$,not ethyl butanoate.

$CH \equiv CH + CO + H_2O \xrightarrow{Ni(CO)_4} \text{Product}$. For this reaction,which statement is false?

Similar Questions

When propyne reacts with aqueous $H_2SO_4$ in the presence of $HgSO_4$,the major product is

The poisonous gas 'Lewisite' is obtained by the reaction of:

Calcium carbide $+ D_2 O \longrightarrow \underline{X} + Ca(OD)_2$.
The hybridisation of carbon atom$(s)$ in $X$ is:

Which of the following reagents will be able to distinguish between $but-1-yne$ and $but-2-yne$?

In the reaction sequence:
$CH_3-C\equiv CH$ $\xrightarrow{CH_3MgBr}$ $CH_4 + (A)$ $\xrightarrow[ (ii) H_2O/H^{\oplus} ]{(i) CO_2}$ $(B)$
$(B)$ will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module