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(D) $NBS$ ($N$-Bromosuccinimide) is a reagent used for free-radical bromination,specifically at the benzylic position.In the given molecule,there are

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(D) $NBS$ ($N$-Bromosuccinimide) is a reagent used for free-radical bromination,specifically at the benzylic position.In the given molecule,there are two benzylic positions:$1$. The $CH(CH_3)$ group between the two rings.$2$. The $CH_2$ group of the ethyl group attached to the right ring.The benzylic radical formed at the $CH_2$ group of the ethyl group is more stable due to resonance with the benzene ring and is less sterically hindered compared to the radical at the $CH(CH_3)$ position.Therefore,the major product is formed by the substitution of a hydrogen atom at the benzylic position of the ethyl group with a bromine atom.The structure of the major product is $CH_3-C_6H_4-CH(CH_3)-C_6H_4-CH(Br)CH_3$.

Identify the major product formed when the following compound reacts with $NBS$ ($N$-Bromosuccinimide):
$CH_3-C_6H_4-CH(CH_3)-C_6H_4-CH_2CH_3 \xrightarrow{NBS} \text{Major Product}$

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Identify the major product formed when the following compound reacts with $NBS$ ($N$-Bromosuccinimide): $CH_3-C_6H_4-CH(CH_3)-C_6H_4-CH_2CH_3 \xrightarrow{NBS} \text{Major Product}$