Ph-CH=C(CH_3)_2 xleftarrow{HBr} A and Ph-CH=C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of $Ph-CH=C(CH_3)_2$ with $HBr$ follows Markovnikov's rule. The electrophilic $H^+$ adds to the carbon with more hydrogens,forming a

Vedclass · Accepted Answer

$A = Ph-CH(Br)-CH(CH_3)_2$ and $B = Ph-CH_2-C(Br)(CH_3)_2$

Vedclass · Answer

(B) The reaction of $Ph-CH=C(CH_3)_2$ with $HBr$ follows Markovnikov's rule. The electrophilic $H^+$ adds to the carbon with more hydrogens,forming a stable benzylic carbocation,which then reacts with $Br^-$ to give $A = Ph-CH(Br)-CH(CH_3)_2$.In the presence of peroxide,the reaction follows the Anti-Markovnikov rule (Kharasch effect) via a free radical mechanism. The bromine radical adds to the terminal carbon to form a stable benzylic radical,which then abstracts a hydrogen atom to give $B = Ph-CH_2-C(Br)(CH_3)_2$.

$Ph-CH=C(CH_3)_2 \xleftarrow{HBr} A$ and $Ph-CH=C(CH_3)_2 \xrightarrow[\text{Peroxide}]{HBr} B$. Identify $A$ and $B$.

Similar Questions

Arrange $HI$,$HCl$,$HBr$,and $HF$ in increasing order of rate of reaction with alkene.

The Diels-Alder reaction will not take place with which of the following reactants?

$H_2O_2$ on reacting with ethene gives:

$CH_3-CH=CH-CH=CH_2 \xrightarrow[Zn]{O_3 / H_2O}$ Which will not form?

Write the mechanism of hydration of ethene to yield ethanol.

Vedclass Test Series

Exam Paper Generator

Online Exam Module