$CH_3-CH_2-CH_2-Cl$ $\xrightarrow{KOH_{(aq)}} X$ $\xrightarrow{H^{+}/\Delta} Y$ $\xrightarrow{Cl_2/H_2O} Z$ (Major); $Z$ is
- A$CH_3-CH(Cl)-CH_2OH$
- B$CH_3-CH(OH)-CH_2Cl$
- C$CH_3-CH(OH)-CH_2OH$
- D$CH_3-CH(Cl)-CH_2Cl$
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Similar Questions
Which of the following alkyl halides is most reactive towards the $S_{N}1$ mechanism?
Difficult
View SolutionExplain the factors favouring $S_{N}2$ reaction.
Medium
View SolutionMatch the following:
Column $I$ Column $II$ $A$. $CH_3-CHBr-CD_3$ on treatment with alc. $KOH$ gives $CH_2=CH-CD_3$ as a major product. $P$. $E1$ reaction $B$. $Ph-CHBr-CH_3$ reacts faster than $Ph-CHBr-CD_3$. $Q$. $E2$ reaction $C$. $Ph-CH_2-CH_2Br$ on treatment with $C_2H_5OD / C_2H_5O^-$ gives $Ph-CD=CH_2$ as the major product. $R$. $E1cb$ reaction $D$. $PhCH_2CH_2Br$ and $PhCD_2CH_2Br$ react with same rate. $S$. First order reaction
| Column $I$ | Column $II$ |
| $A$. $CH_3-CHBr-CD_3$ on treatment with alc. $KOH$ gives $CH_2=CH-CD_3$ as a major product. | $P$. $E1$ reaction |
| $B$. $Ph-CHBr-CH_3$ reacts faster than $Ph-CHBr-CD_3$. | $Q$. $E2$ reaction |
| $C$. $Ph-CH_2-CH_2Br$ on treatment with $C_2H_5OD / C_2H_5O^-$ gives $Ph-CD=CH_2$ as the major product. | $R$. $E1cb$ reaction |
| $D$. $PhCH_2CH_2Br$ and $PhCD_2CH_2Br$ react with same rate. | $S$. First order reaction |
The dehydrobromination of $2$-bromobutane results in the formation of which of the following?
Difficult
View SolutionConsider the above chemical reaction. Product $A$ is:
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