100 mL of PH_3 when completely decomposed pr | vedclass

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(A) The decomposition reaction is: $PH_{3(g)} \longrightarrow P_{(s)} + \frac{3}{2} H_{2(g)}$According to the stoichiometry of the reaction,$1 \ volum

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$50 \ mL$ increase

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(A) The decomposition reaction is: $PH_{3(g)} \longrightarrow P_{(s)} + \frac{3}{2} H_{2(g)}$According to the stoichiometry of the reaction,$1 \ volume$ of $PH_3$ produces $\frac{3}{2} \ volumes$ of $H_2$ gas.At $t=0$: Initial volume of $PH_3 = 100 \ mL$.At $t=	ext{final}$: Volume of $H_2$ produced = $\frac{3}{2} 	imes 100 \ mL = 150 \ mL$.Change in volume of gas = $V_{	ext{final}} - V_{	ext{initial}} = 150 \ mL - 100 \ mL = 50 \ mL$ increase.

$100 \ mL$ of $PH_3$ when completely decomposed produces phosphorus and hydrogen. The change in volume of the gas is
$PH_{3(g)} \longrightarrow P_{(s)} + \frac{3}{2} H_{2(g)}$

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$100 \ mL$ of $PH_3$ when completely decomposed produces phosphorus and hydrogen. The change in volume of the gas is$PH_{3(g)} \longrightarrow P_{(s)} + \frac{3}{2} H_{2(g)}$