B(OH)_3 + NaOH rightleftharpoons NaBO_2 + Na[ | vedclass

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(A) Boric acid,$B(OH)_3$,is a weak monobasic Lewis acid. It reacts with $NaOH$ to form $Na[B(OH)_4]$. The addition of cis-$1, 2-$diols (like glycerol

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Addition of cis-$1, 2-$diol

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(A) Boric acid,$B(OH)_3$,is a weak monobasic Lewis acid. It reacts with $NaOH$ to form $Na[B(OH)_4]$. The addition of cis-$1, 2-$diols (like glycerol or mannitol) forms a stable chelate complex with the borate ion,$[B(OH)_4]^-$. According to Le Chatelier's principle,the removal of the product $[B(OH)_4]^-$ from the equilibrium mixture shifts the reaction in the forward direction,thereby increasing the effective acidity of $B(OH)_3$.

$B(OH)_3 + NaOH \rightleftharpoons NaBO_2 + Na[B(OH)_4] + H_2O$
How can this reaction be made to proceed in the forward direction?

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$B(OH)_3 + NaOH \rightleftharpoons NaBO_2 + Na[B(OH)_4] + H_2O$How can this reaction be made to proceed in the forward direction?