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(B) The $photochemical \ chlorination$ of methane is a free radical chain reaction. Oxygen $(O_2)$ acts as an inhibitor in this process because it rea

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inhibits the reaction for some time.

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(B) The $photochemical \ chlorination$ of methane is a free radical chain reaction. Oxygen $(O_2)$ acts as an inhibitor in this process because it reacts with the free radical intermediates (like $CH_3^{\bullet}$) to form stable peroxy radicals. This effectively terminates the chain reaction,thereby inhibiting the reaction for some time until the oxygen is consumed.

The addition of oxygen to the reaction mixture of methane and chlorine in $photochemical \ chlorination$:

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