The reaction of lithium di-3-pentylcuprate wi | vedclass

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(C) The reaction is a Corey-House synthesis (alkylation of organocopper reagents). Lithium di-$3-$pentylcuprate is $(CH_3CH_2CH(CH_2CH_3))_2CuLi$. Eth

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$3-$ethylpentane

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(C) The reaction is a Corey-House synthesis (alkylation of organocopper reagents). Lithium di-$3-$pentylcuprate is $(CH_3CH_2CH(CH_2CH_3))_2CuLi$. Ethyl bromide is $CH_3CH_2Br$. The reaction involves the coupling of the alkyl group from the cuprate with the alkyl group from the halide: $(CH_3CH_2CH(CH_2CH_3))_2CuLi + CH_3CH_2Br \rightarrow CH_3CH_2CH(CH_2CH_3)CH_2CH_3 + CH_3CH_2Cu + LiBr$. The product is $CH_3CH_2CH(CH_2CH_3)CH_2CH_3$. Naming the structure: The longest chain is $6$ carbons long (hexane),with an ethyl group at position $3$. Thus,the structure is $3-$ethylhexane. Wait,checking the carbon count: $3-$ethylhexane has $8$ carbons $(C_8H_{18})$. Let's re-evaluate: The reactant is lithium di-$3-$pentylcuprate ($C_5H_{11}$ group) and ethyl bromide ($C_2H_5$ group). $C_5H_{11} + C_2H_5 = C_7H_{16}$. The structure formed is $CH_3CH_2CH(CH_2CH_3)CH_2CH_3$ which is $3-$ethylpentane. $3-$ethylpentane has $7$ carbons $(C_7H_{16})$.

The reaction of lithium di-$3-$pentylcuprate with ethyl bromide yields an alkane with the molecular formula $C_7H_{16}$. What is the structure of the alkane?

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