What is the major product of the reaction CH_ | vedclass

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(C) The reaction of an alkene with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition rule (Kharasch effect or peroxide effect).I

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$CH_2Br-(CH_2)_9COOH$

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(C) The reaction of an alkene with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition rule (Kharasch effect or peroxide effect).In this reaction,the $Br^-$ radical adds to the carbon atom of the double bond that has more hydrogen atoms.The reaction is: $CH_2 = CH-(CH_2)_8COOH + HBr \xrightarrow{	ext{Peroxide}} CH_2Br-CH_2-(CH_2)_8COOH$.Simplifying the product,we get $CH_2Br-(CH_2)_9COOH$.

What is the major product of the reaction $CH_2 = CH-(CH_2)_8COOH + HBr \xrightarrow{\text{Peroxide}} \dots$?

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