The addition of HI to the double bond of prop | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of $HI$ with propene $(CH_3-CH=CH_2)$ follows Markovnikov's rule. In the first step,the electrophile $H^+$ attacks the double bond to

Vedclass · Accepted Answer

More stable carbocation

Vedclass · Answer

(A) The reaction of $HI$ with propene $(CH_3-CH=CH_2)$ follows Markovnikov's rule. In the first step,the electrophile $H^+$ attacks the double bond to form a carbocation intermediate. Two possible carbocations can be formed: $CH_3-CH^+-CH_3$ (secondary carbocation) and $CH_3-CH_2-CH_2^+$ (primary carbocation). The secondary carbocation is more stable due to the inductive effect and hyperconjugation of the two adjacent methyl groups. Therefore,the reaction proceeds through the more stable carbocation to form isopropyl iodide $(CH_3-CH(I)-CH_3)$ as the major product.

The addition of $HI$ to the double bond of propene gives isopropyl iodide as the major product because the addition proceeds through:

Similar Questions

The order of increasing reactivity towards $HCl$ of the following compounds will be:
$(1)$ $CH_2 = CH_2$
$(2)$ $(CH_3)_2C = CH_2$
$(3)$ $CH_3CH = CHCH_3$

Olefins can be hydrogenated by

Acid-catalyzed hydration of alkenes,except ethene,leads to the formation of:

In which of the following,addition of $HBr$ does not take place against Markownikoff's rule,or for which is the Anti-Markownikoff addition of $HBr$ not observed?

The major product of the following chemical reaction is: $CH_3-CH(CH_3)-CH=CH_2 + HBr \xrightarrow{(C_6H_5CO)_2O_2} ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module