The reaction of 2-pentyne with dilute H_2SO_4 | vedclass

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(C) The hydration of alkynes in the presence of dilute $H_2SO_4$ and $HgSO_4$ follows Markovnikov's addition.For a symmetrical alkyne like $CH_3-CH_2-

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$2-$pentanone

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(C) The hydration of alkynes in the presence of dilute $H_2SO_4$ and $HgSO_4$ follows Markovnikov's addition.For a symmetrical alkyne like $CH_3-CH_2-C \equiv C-CH_3$ ($2-$pentyne),the addition of water across the triple bond results in an enol intermediate.$CH_3-CH_2-C \equiv C-CH_3 + H_2O \xrightarrow{Hg^{2+}, H^+} CH_3-CH_2-C(OH)=CH-CH_3$ (enol).This enol undergoes tautomerization to form a mixture of ketones.Specifically,the oxygen can attach to either $C-2$ or $C-3$ of the pentane chain.Thus,the reaction yields a mixture of $2-$pentanone $(CH_3-CO-CH_2-CH_2-CH_3)$ and $3-$pentanone $(CH_3-CH_2-CO-CH_2-CH_3)$.

The reaction of $2-$pentyne with dilute $H_2SO_4$ and $HgSO_4$ yields...............

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